Question

Calculate the volume of 64g of oxygen, 10g of ammonia, 100g of hydrogen.​

Answer 1

Answer:

4 mol

Explanation:

2H

2

+O

2

→2H

2

O

10 g of hydrogen (molar mass 2 g/mol) =

2 g/mol

10 g

= 5 mol

64 of oxygen (molar mass 32 g/mol) =

32 g/mol

64 g

= 2 mol

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.

Answer 2

Answer:

2H  

2

​

+O  

2

​

→2H  

2

​

O

10 g of hydrogen (molar mass 2 g/mol) =  

2 g/mol  

10 g  

​

= 5 mol  

64 of oxygen  (molar mass 32 g/mol) =  

32 g/mol  

64 g  

​

= 2 mol  

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.

Source: toppr