Question

Calculate the volume % of Chlorine at equilibrium in PCL 5 under a total pressure in 1.5 ATM (Kp= 0.202)

Answer 1

Answer:

B::C

Solution :

t=0(moles)t=teqPCl5(g)aa−x⇔Pcl3(g)0x+Cl2(g)0x

Kp=PPCl3.PCl2PPCl5=[xa+xP][xa+xP]a−xa+xP

⇒Kp=x2Pa2−x2=α2P1−α2=0.3[α=xa]⇒α=16−−√

%Cl2=xa+x=α1+α×100%=28.6%

Hope it helps you.

Answer 2

B::C

Solution :

t=0(moles)t=teqPCl5(g)aa−x⇔Pcl3(g)0x+Cl2(g)0x

Kp=PPCl3.PCl2PPCl5=[xa+xP][xa+xP]a−xa+xP

⇒Kp=x2Pa2−x2=α2P1−α2=0.3[α=xa]⇒α=16−−√

%Cl2=xa+x=α1+α×100%=28.6%

Hope it helps you.