Calculate the volume of co2 at stp obtained by heating 25g of caco3
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CaCO3 molar mass is 100 u.
or it can be represented as 100 grams when it is expressed as molecular mass.
CaCO3 ---------> CaO + CO2
CO2 molar mass is 44 u, it's molecular mass is 44 grams.
This implies 100 g of CaCO3 gives 44 g of CO2.
Therefore 25 g of CaCO3 gives 44/100 * 25 = 11 grams.
One mole of CO2 is 44 grams.
Therefore in 11 grams of CO2 , there would be 1/44 * 11 = 0.25 moles.
one mole of CO2 occupies 22.4 L of volume, therefore 0.25 moles of CO2 has a volume of 22.4 * 0.25 =
5.6 L of volume.
THANK YOU
CaCO3 molar mass is 100 u.
or it can be represented as 100 grams when it is expressed as molecular mass.
CaCO3 ---------> CaO + CO2
CO2 molar mass is 44 u, it's molecular mass is 44 grams.
This implies 100 g of CaCO3 gives 44 g of CO2.
Therefore 25 g of CaCO3 gives 44/100 * 25 = 11 grams.
One mole of CO2 is 44 grams.
Therefore in 11 grams of CO2 , there would be 1/44 * 11 = 0.25 moles.
one mole of CO2 occupies 22.4 L of volume, therefore 0.25 moles of CO2 has a volume of 22.4 * 0.25 =
5.6 L of volume.
THANK YOU
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