Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km per hour
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Answered by
1
Mass of car, m = 1500 kg
velocity, v = 60 km/h = 60 \times \frac{5}{18}=16.67\ ms^{-1}60×185=16.67 ms−1
Kinetic energy possessed by the car = \frac{1}{2}21 mv²
⇒ KE = \frac{1}{2} \times 1500 \times 16.67^2=208416.7\ J=208.4\ kJ21×1500×16.672=208416.7 J=208.4 kJ
To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 KJ.
velocity, v = 60 km/h = 60 \times \frac{5}{18}=16.67\ ms^{-1}60×185=16.67 ms−1
Kinetic energy possessed by the car = \frac{1}{2}21 mv²
⇒ KE = \frac{1}{2} \times 1500 \times 16.67^2=208416.7\ J=208.4\ kJ21×1500×16.672=208416.7 J=208.4 kJ
To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 KJ.
Answered by
2
Hey there!
Given,
Mass of car (m) = 1500 kg
Velocity of car ( v) = 60 km/h = 60 * 5/18 m/s
Work done = ?
Here,
Work done = Kinetic Energy
= 1/2 * mv²
= 1/2 * 1500 * 60 * (5/18) J
= 20.8 × 10⁴ J (←Answer)
Hope It Helps You!
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