Calculate the volume of CO2 liberated at stp by heating 1000g of CaCo3 which 80% pure CaCO3___CaO+CO2
Answers
Answered by
1
Answer:
179.2L
Explanation:
pure CaCO3 = 800g
Now, CaCO3 =CaO +CO2
according to question
100g of CaCO3 = 22.4L of CO2 at STP
800gof CaCO3 =( 22.4/100)×800
= 22.4×8
= 179.2 L
Similar questions