find the sum of 10 terms of an AP 2, 6, 10,.......... ( sn= n/2 [ 2a+ n-1) d]formula
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S10=120
Step-by-step explanation:
a=2
d=6-2=4
S10=10/2(2*2+(10-1)4)
=5(4+36)
=5(40)
=120
Hope it helps :)
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