Question

Calculate the volume of gas X at S.T.P. if it occupies 380 litres at 300 K and

70 cm of mercury.​

Answer 1

We know that at S.T.P

T= 273 K

P = 760 mm Hg

Hope, it Helps!!

Answer 2

The volume of gas X at S.T.P. if it occupies 380 litres at 300 K and   70 cm of mercury is 318.5 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas (STP) = 1 atm = 76 cm of Hg

$P_2$ = final pressure of gas = 70 cm of Hg

$V_1$ = initial volume of gas  (STP) = ?

$V_2$ = final volume of gas = 380 L

$T_1$ = initial temperature of gas (STP)  = 273K

$T_2$ = final temperature of gas = 300 K

Now put all the given values in the above equation, we get:

$\frac{76\times V_1}{273K}=\frac{70\times 380}{300K}$

$V_1=318.5L$

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