Question

calculate the volume of HCL gas formed and chlorine gas required when 40ml of methane reacts completely with chlorine at STP.

CH4+2CL2-----» CH2CL2+ 2HCL

Answer 1

CH4 + 2Cl2 → CH2Cl2 +2 HCl

Here, we see that 1 mole of CH4 react with 2 Mole of Cl2 form 1 mole of C2H2 and 2mole HCl.

it means 1 mole of CH4 , forms 2 mole of HCl .

so, 1 volume of CH4 forms 2volume of HCl.

hence,
40 ml of CH4 forms 2 × 40ml HCl

hence, volume of HCl = 80 ml

Answer 2

The reaction would be as follows:-

CH4 + 2Cl2 → CH2Cl2 +2 HCl

Now from the reaction stoichiometry we can find that:-

1 mole of CH4 forms 2 mole of HCl

Therefore,40 ml of CH₄ forms (40*2)ml of HCl that is 80 ml of HCl.

Hope it helps!