Question

pinky scored 40 marks in test getting 3 marks for each right answer and and loosing 1 mark for each wrong answer had 4 marks been awarded for each correct answer and 2 marks deducted for each wrong answer then pinky again would have scored 40 marks how many questions were there in the test .
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Answer 1

Answer:

Step-by-step explanation:

CONDITION 1.

Marks awarded for x right answers= 3x

Marks lost for y wrong answers = y×1= y

3x - y = 40………….(1)

CONDITION 2

Marks awarded for x right answers= 4x

Marks lost for y wrong answers = y×2= 2y

4x - 2y = 40…………(2)

Multiply equation 1 by 2 and subtract equation 2

6x - 2y = 80

4x - 2y = 40        [By elimination method]

(-)  (+)   (-)

-----------------

2x = 40

x = 40 /2

x = 20

On putting the value of x in equation 1.

3x -y = 40

3(20) - y = 40

60 - y = 40

-y  = 40 - 60

-y = -20

y = 20

Total number of questions in the test= x+y = 20 + 20= 40.

Hence, there were total 40 questions in the test

HOPE THIS WILL HELP YOU..

Answer 2

Answer:

$\huge{\mathcal{\underline{\green{Answer}}}}$

Let x be the number of right answers and y be the number of wrong answers.

∴ According to the question ,

3x−y=40⟶(i)

and , 2x−y=25⟶(ii)

On substraction : x=15

putting the value of x in ⟶(i)

3(15)−y=40

y=5

∴ Number of right answers=15 answers

Number of wrong answers=5 answers.

Total Number of questions 5+15=20