Calculate the volume of hydrogen liberated at 27°c and 760mm pressure by treating 1.2g of magnesium with access of HCL
Answers
Answered by
20
hey
here is your answer
the balanced equation is:
mg+2hcl+mgcl2+h2
24kg of mg liberate hydrogen=22.4litre
1.2g mg will liberate hydrogen:
22.4\24×1.2=1.12litre
volume of hydrogen under given condition can be calculated by applying-
p1v1\t1=p2v2\t2
p1=760mm
t1=273k
v1=1.12litres
p2=760mm
t2=(27+273)=300k
v2=?
v2=760×1.12÷273×300÷760=1.2308 litres .
hope it helps you.
please mark me brainlist
Answered by
2
Answer:
1.23 is the final answer of this question
Similar questions