Question

calculate the volume of oxygen required for complete combustion of 0.25 mole of methane at STP

Answer 1

CH4 +  2  O2----------->    CO2 + 2  H2O

1    mole of CH4   reacts with  2 moles of oxygen

0.25 moles of CH4--------------   ?

       0.25*2 = 0.50 moles *22.4 liters at STP

                             = 11.2 LITERS.

Answer 2

Answer:

for Ethane

c2h6

Explanation:

1(mole) 30 = 22.4li

x = 30 / 22.4

x = 1.33