calculate the volume of oxygen when 165g red-lead allowed to heat
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The formula of red lead is Pb3O4
2PbO4=6PbO+O2
Means on heating 2 mole of red lead
1 mole of O2 is produced
No of of red lead in question=165/685=0.24
Therefore moles of of O2 produced
0.24/2=0.12
Therefore volume of O2=0.12*22.4=2.6 litre
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2PbO4=6PbO+O2
Means on heating 2 mole of red lead
1 mole of O2 is produced
No of of red lead in question=165/685=0.24
Therefore moles of of O2 produced
0.24/2=0.12
Therefore volume of O2=0.12*22.4=2.6 litre
Pls mark my answer brainleast
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