Question

Calculate the volume of SO2 liberated at S.T.P when 15 g of copper reacts with
excess of conc. H2SO4.

Answer 1

Answer:

5.376 liters of SO2

Explanation:

1 mole of Cu = 63.5 g

? moles of Cu = 15g

15/63.5 = 0.236 = 0.24 moles (approx)

Cu + 2H2SO4 ----> CuSO4 + 2H2O + SO2

1 mole of Cu reacts with H2SO4 to form 1 mole of SO2.

0.24 moles react with H2SO4 to form ? moles of SO2

0.24/ 1 moles of SO2

1 mole of SO2   =  22.4 liters of SO2

0.24 moles of SO2 = ? liters of SO2

0.24 x 22.4 = 5.376 liters of SO2