calculate the volume of STP in 0.84 gram of Nitrogen
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1.344 L is the volume of 0.84 Nitrogen in STP
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At STP
temperature = 288.7 k
pressure = 101.325 kpa
so
PV= nRT
V= nRT/P
n= 1 mole at stp
so
V= RT/ P
V = (8.31451× 288.7)/ 101.325
V= 2400.39/101.325
V = 23.69 l
temperature = 288.7 k
pressure = 101.325 kpa
so
PV= nRT
V= nRT/P
n= 1 mole at stp
so
V= RT/ P
V = (8.31451× 288.7)/ 101.325
V= 2400.39/101.325
V = 23.69 l
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