Question

if the complex number z=x+iy satisfies the condition (z+1)=1 , then z lies on

Answer 1

Answer : Circle with centre (-1,0) and radius 1

Explanation :

|z+1|=1|z+1|=1

|(x+1)+iy|=1|(x+1)+iy|=1

(x+1)2+y2=12(x+1)2+y2=12

Which is a Circle with centre (-1,0) and radius 1 .hope this help

Answer 2

Step-by-step explanation:

|z +1|=1 ⇒ |(x +1)+iy| = 1

⇒ (x +1)2 + y2 = 1

which is a circle with centre (–1, 0) and radius 1

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