calculate the volume of the solid bounded by the surface z=4x^2+4y^2, z= x^2+y^2, z = 4
Answers
Answered by
0
Volume = lbh
ATQ,
Volume = (4x^2+4y^2)(x^2+y^2)(4)
=4x^2 (x^2+y^2)+4y^2 (x^2+y^2)(4)
=(4x^4+4x^2y^2+4x^2y^2+4y^4)(4)
=(4x^4+8x^2y^2+4y^4)(4)
=4(4x^4)+4(8x^2y^2)+4(4y^4)
=16x^4+32x^2y^2+16y^4
=16 (x^4 + 2x^2y^2 + y^4).
ATQ,
Volume = (4x^2+4y^2)(x^2+y^2)(4)
=4x^2 (x^2+y^2)+4y^2 (x^2+y^2)(4)
=(4x^4+4x^2y^2+4x^2y^2+4y^4)(4)
=(4x^4+8x^2y^2+4y^4)(4)
=4(4x^4)+4(8x^2y^2)+4(4y^4)
=16x^4+32x^2y^2+16y^4
=16 (x^4 + 2x^2y^2 + y^4).
Similar questions