Question

Calculate the volume of water which could be added to 20 ml of 0.65 m HCl to dilute the solution to 0.2 m?

Answer 1

$\huge\bf{Answer}$

M1 = 0.65 M

Initial volume =V1= 20 mL

M1 = 0.2 M

final volume = V2 = ?

M1 * V1 =M1 * V2

(0.65)(20) = (0.2) x V2

V2 = (0.65 x 20) / 0.2

V2 = 65ml

Volume of H2Oto be added = V2 - V1

=65ml - 20ml = 45ml

$\huge\bf{Thanks}$

Answer 2

Answer:

Here is your answer

Explanation:

M1 = 0.65 M

Initial volume =V1= 20 mL

M1 = 0.2 M

final volume = V2 = ?

M1 * V1 =M1 * V2

(0.65)(20) = (0.2) x V2

V2 = (0.65 x 20) / 0.2

V2 = 65ml

Volume of H2Oto be added = V2 - V1

=65ml - 20ml = 45ml

Hope it was helpful