Question

kx^2+(√3-√2)x-1=0;x=1/√3 find value of k​

Answer 1

Answer:

Given, k

2

x+2x+1=0 ______ (1) where a=k, b=2, c=1

since the equation (1) has distinct roots,

b

2

−4ac>0

⇒2

2

−4k>0

⇒4−4k>0

⇒−4k>−4

⇒4k<4

⇒k<1

∴ whenever k < 1 the given equation (1) will have distinct roots.