Question

Calculate the volume of wood of mass 6000 kg if the density of wood is 0.8 gcm^3

Answer 1

Answer:

the volume of the wood will be 7.5m^3.

Explanation:

first convert the density in terms of m and kg which comes out to be 0.8×10^3kgm^-3.then apply the formula

density=mass/volume

and the volume will come out to be 7.5m^3.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Volume\:of\:wood=75\times 10^{5}\:cm^{3}\:or\:7500\:L}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given : }}$

$\tt: \implies Mass \: of \: wood = 6000 \: kg$

$\tt: \implies Density\: of \: wood = 0.8 \:g/ {cm}^{3}$

$\red{\underline \bold{To \: Find : }}$

$\tt: \implies Volume \: of \:wood = ?$

• Given Question

$\tt \circ \: Mass = 6000 \times 1000 = 6 \times {10}^{6} \: g$

$\bold{As \: we \: know \: that}$

$\tt: \implies Density = \frac{Mass}{Volume}$

$\tt: \implies 0.8 \times \frac{g}{cm ^{3} } = \frac{6 \times {10}^{6} }{Volume} \times g$

$\tt: \implies Volume = \frac{6 \times {10}^{6} }{0.8} \times \frac{g \times {cm}^{3} }{g}$

$\tt: \implies Volume = \frac{6 \times 10^{7} }{8} \times {cm}^{3}$

$\tt: \implies Volume = 0.75 \times {10}^{7} \: cm^{3}$

$\green{\tt: \implies Volume = 75 \times {10}^{5} \: {cm}^{3} }$

$\green{\tt\therefore Volume\:of\:wood\:is\:75\times 10^{5}\:cm^{3}\:or\:7500\:litre}$

$\blue {\boxed{ \bold{Some \: related \: formula}}}$

$\orange{ \tt \circ \: Kinetic \: energy = \frac{1}{2} {mv}^{2} }$

$\orange{ \tt \circ \:Potential \: energy = mgh }$

$\orange{ \tt \circ \: Linear \: momentum=mv}$

$\orange{\tt\circ\: Pressure=\frac{Force}{Area}}$