Question

Calculate the wave length of a rotation emitted by the He+ atom where electron jumps from 3rd shell to ground shell.​

Answer 1

Answer:

V

=R[

x

1

2

1

−

x

2

2

1

]

=109677[

4

2

1

−

2

2

1

]cm

−1

[Here R=108677 cm

−1

,x

1

=4;x

2

=2

=20564.4 cm

−1

]

λ=

V

1

=

20564.4

1

=486×10

−7

cm

=486×10

−9

cm

=486 nm.