Question

* Calculate the wave number of
the emitted spectral line
when an electron jumps from
n-3 to n=1 in a hydrogen
atom.
​

Answer 1

Answer:

Correct option is

A

n=3 to n=1

Wave number of spectral line in emission spectrum of hydrogen,

v

ˉ

=R

H

(

n

1

2

1

−

n

2

2

1

) ...(i)

Given,

v

ˉ

=

9

8

R

H

On putting the value of

v

ˉ

in Eq. (i), we get-

9

8

R

H

=R

H

(

n

1

2

1

−

n

2

2

1

)

9

8

=

(1)

2

1

−

n

2

2

1

9

8

−1=

n

2

2

1

3

1

=

n

2

1

∴n

2

=3

Hence, electron jumps from n

2

=3 to n

1

=1