Calculate the wavelength and frequency emitted for an electron in H atom from 6th level to the ground state ( n= 1 ). In which region the spectral line belongs to?
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Here we can consider Rydberg's equation,
i.e ,
1/λ = R [ 1/n₁² - 1/n₂² ]
Here,
1/λ is the wave number
R is the Rydberg's constant ( 109677 )
n₁ , n₂ represents the region in spectral line. ( n₁ = 1 & n₂ = 6)
Using Rydberg's equation,
1/λ = 109677 [ 1/1² - 1/6² ]
=109677 × 0.9722
= 106630.9777 cm⁻¹ //
∴ λ = 1/106630.977
= 9.37 × 10⁻⁶ cm //
F ( frequency) = C / λ
= 3 × 10¹⁰ / 9.37 × 10⁻⁶ [ used 3 × 10¹⁰ coz answer should be in centimeters ]
= 3.19 × 10¹⁵
= 3.2 ×10¹⁵ Hz //
∴ λ = 9.37 × 10⁻⁶ cm
&
F = 3.2 ×10¹⁵ Hz
Since, n₁ = 1 , the radiation belongs to UV REGION
i.e ,
1/λ = R [ 1/n₁² - 1/n₂² ]
Here,
1/λ is the wave number
R is the Rydberg's constant ( 109677 )
n₁ , n₂ represents the region in spectral line. ( n₁ = 1 & n₂ = 6)
Using Rydberg's equation,
1/λ = 109677 [ 1/1² - 1/6² ]
=109677 × 0.9722
= 106630.9777 cm⁻¹ //
∴ λ = 1/106630.977
= 9.37 × 10⁻⁶ cm //
F ( frequency) = C / λ
= 3 × 10¹⁰ / 9.37 × 10⁻⁶ [ used 3 × 10¹⁰ coz answer should be in centimeters ]
= 3.19 × 10¹⁵
= 3.2 ×10¹⁵ Hz //
∴ λ = 9.37 × 10⁻⁶ cm
&
F = 3.2 ×10¹⁵ Hz
Since, n₁ = 1 , the radiation belongs to UV REGION
Kimmus:
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