calculate the wavelength ,if the work function is 2.0ev and stopping potential is 0.50 V
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use Einstein theory of photoelectric effect .
eVo=hc/lemda - work function
where Vo is stopping potential , h is plank constant and lemda is wavelength
now ,
(0.5)eV=1237.5/lemda-2.0 eV
2.5eV=1237.5/lemda
lemda=(1237.5/2.5 ) nm
=495 nm
eVo=hc/lemda - work function
where Vo is stopping potential , h is plank constant and lemda is wavelength
now ,
(0.5)eV=1237.5/lemda-2.0 eV
2.5eV=1237.5/lemda
lemda=(1237.5/2.5 ) nm
=495 nm
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