Question

Calculate the wavelength of a photon with 3.2 x 10-19 J of energ
A. 210 nm
B.420 nm
C.530 nm
D. 620 nm​

Answer 1

A thermostat is a component which senses the temperature of a physical system and performs actions so that the system's temperature is maintained near a desired setpoint.

Answer 2

(D) The wavelength of a photon with 3.2 × 10⁻¹⁹ J of energy is 620 nm.

Given :

Energy of the photon (E) = 3.2 × 10⁻¹⁹ J

To Find :

Wavelength of the photon

Solution :

We know,

   Energy of the photon (E) = $\frac{hc}{Wavelength}$

∴ Wavelength (λ) = $\frac{hc}{E}$

                            =  $\frac{6.625 * 10^-^3^4 * 3 * 10^8}{3.2 * 10^-^1^9}$

                            =  $\frac{19.875 * 10^-^2^6}{3.2 * 10 ^-^1^9}$

                            = 6.21 × 10⁻⁷ m

                            = 621 nm

Therefore, the wavelength of the photon is 621 nm.

The value of wavelength is close to option (d) i.e., 620 nm.

Hence, option (d) is correct.