Question

find the distance between (1,5)and(x-5) is 8.find x​

Answer 1

Step-by-step explanation:

8=√(x2-x1)2+(y2-y1)2

squaring both sides

64=x2-x+1

x2-x+1=0

Answer 2

Answer:

Let A(1, 5) be (x1, y1)

and B(x, -5) be (x2, y2)

Using distance formula,

d(A, B) = √(x2-x1) ^2 + ( y2-y1) ^2

8 = √(x-1) ^2 + (-5-5) ^2

8 = √x^2 - 2x + 1 + 100

Squaring on both sides,

64 = x^2 - 2x + 101

Therefore,

x^2 - 2x + 101-64 = 0

x^2 - 2x + 37 = 0

Factorise it further you will get your answer.

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