Question

Calculate the wavelength of an electron moving with a velocity of `2.75times10^(8)ms^(-1)`. -​

Answer 1

Answer:

2.645 × 10⁴ m

Explanation:

The wavelength of an electron can easily be found out by De-Broglie Equation

$\implies\lambda\:=\:\frac{h}{m\times v}$

here,

• h = Planck's constant = 6.626 × 10⁻³⁴ J s
• m = mass of electron = 9.11 ×10⁻³¹ kg
• v = velocity of electron = 2.75 × 10⁸ m/ s

$\implies \lambda\:=\frac{6.626\:\times10^{-34}}{9.11\times10^{-31}\:\times\:2.75\times10^{8}}$

$\implies \lambda\:=\:0.26448\:\times\:10^{5}\\\implies \lambda\:=\:2.645\:\times\:10^4\: m$

                             

Hope this helps!