Question

calculate the wavelength of an electron with a velocity of 2.05× 107​

Answer 1

Answer:

formula is lamda=h\m×v

Explanation:

put the values on the formula u get the answer

Answer 2

V= 2.05 x107 (given)

According to de Broglie’s equation,

Where, λ = wavelength of moving particle

m = mass of particle (9.10939 x 10-31)

v = velocity of particle

h = Planck’s constant (6.62 x 10-34)

Substituting the values in the expression of λ:

Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.

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