calculate the wavelength of limiting lines in lyman series
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3
Explanation:
wavelength of limiting line of Lyman series is 911 A˚. The atomic number of the element which emits minimum wavelength of 0.7 A˚ of X-rays will be. A
Answered by
1
The wavelength of limiting line of Lyman series is 911
A
˚
. The atomic number of the element which emits minimum wavelength of 0.7
A
˚
of X-rays will be
E=
λ
hc
=kZ
2
(
n
1
2
1
−
n
2
2
1
)
For Lyman, n
1
=1 and limiting line means the electron is ejected from orbit n
2
= infinity
λ
1
=kZ
2
(
n
1
2
1
−
n
2
2
1
For case 2, same conditions except different atomic number.
λ
2
λ
1
=Z
2
0.7
911
=Z
2
Z=37
i hope it helps you
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