calculate the wavelength of limiting lines in Lyman series explain
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Answer:
E=
λ
hc
=kZ
2
(
n
1
2
1
−
n
2
2
1
)
For Lyman, n
1
=1 and limiting line means the electron is ejected from orbit n
2
= infinity
λ
1
=kZ
2
(
n
1
2
1
−
n
2
2
1
For case 2, same conditions except different atomic number.
λ
2
λ
1
=Z
2
0.7
911
=Z
2
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