Calculate the wavelength of the Balmer line corresponding to n2=4.
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Answer:
n1=2 n2=4
then
1/lambda=R(1 /n1^2-1/n2^2)
1/lambda=R(1/4-1/16)
1/lambda=R(4-1/16)
1/lambda=3R/16
lambda= 16/3R
lambda=16/3.291×10^7
lambda=4.8×10^-7
Explanation:
R=1.097×10^7
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