Question

Calculate the wavelength of the first line and the last line in the Lyman series of

hydrogen atom.
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Answer 1

Explanation:

91.2 nm

The Lyman limit is the short-wavelength end of the hydrogen Lyman series, at 91.2 nm (912 Å). It corresponds to the energy required for an electron in the hydrogen ground state to escape from the electric potential barrier that originally confined it, thus creating a hydrogen ion.

Answer 2

Explanation:

1/lambda = R(1/ (n1)^2 - (n2)^2)-Z^2

where,

R = Rydbergs constant (Also written Eh)

Z = atomic number

Since the question is asking for 1st line of Lyman series therefore.

N1=1 and N2 =2

since the electron is de-exited from 1(st)exited state (i.e n=2) to ground state (i.e n=1)for first line of Lyman series.