Question

calculate the wavelengths of sound at the extremes of the audible range,20 and 20,000Hz in 30.0C air assume that the frequency values are accurate to two significant figures?​

Answer 1

Answer:

By the end of this section, you will be able to:

Define pitch.

Describe the relationship between the speed of sound, its frequency, and its wavelength.

Describe the effects on the speed of sound as it travels through various media.

Describe the effects of temperature on the speed of sound.

Answer 2

Answer:

lamda =16.6m for 20Hz and 0.0166m for 20000Hz

Explanation:

f1=20Hz and f2=20000Hz

and speed of sound in air at 30°C is 332 ms.

v=f(lamda)

f1=20Hz

lamda=v/f1

lamda=332/20

lamda=16.6 m

f2=20000Hz

lamda=v/f

lamda=332/20000

lamda=0.016Hz