The sum ot 10th 11th and 12th term of AP with 21 term
is 129 and the sum of last three term is 237. find the
arithmetic progression
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The sum of 10th, 11th and 12th term is 129. So, the middle three terms are = (a11 - 1),(a11) and (a11 + 1) = a10, a11 and a12. sum of the 10t, 11th and 12th terms is 129. Also given that the sum of the last three terms is 237.
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