Calculate the wavenumber for the shortest wavelength
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Explanation:
The shortest wavelength transition in the Barlmer series corresponds to the transitionn = 2 → n = ∞. Hence, n1 = 2, n2 = ∞ Balmer
Putting the values in the equation we get, wavenumber=27419.25/cm.
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Explanation:
Wave number=1/lambda
Radiation. Gamma has the least wavelength of<1
Wave no.= 1/1= approx.1
Colour. Violet has least wavelength of 380 pick meters
Wavwe number = 1/ 380
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