Question

calculate the wavlenght from the balmer formula when n=3

Answer 1

Hey There, 

For Hydrogen Atom, for Balmer Series, the formula for wavelength is given by: 

$\frac{1}{\lambda}=R\left(\frac{1}{2^2}-\frac{1}{n^2}\right) \\ \\ \\ \implies \frac{1}{\lambda} = R\left(\frac{1}{4}-\frac{1}{9}\right) \\ \\ \\ \implies \frac{1}{\lambda} = R\times \frac{5}{36} \\ \\ \\ \implies \lambda = \frac{36}{5R} \\ \\ \\ \implies \lambda = \frac{36}{5\times 1.097\times 10^7} \\ \\ \\ \implies \lambda \approx 32.82 \times 10^{-7} \, m \\ \\ \\ \implies \boxed{\lambda \approx 3.28 \times 10^{-6} \, m}$


Hope it helps
Purva
Brainly Community

Answer 2

Answer:

The wavelength is  $\lambda \approx 3.28 \times 10^{-6} \, m$      

Step-by-step explanation:

To find : Calculate the wavelength from the balmer formula when n=3 ?

Solution :

As n=3 i.e. for Hydrogen Atom,

Balmer Series, the formula for wavelength is given by

$\frac{1}{\lambda}=R\left(\frac{1}{2^2}-\frac{1}{n^2}\right)$

$\frac{1}{\lambda} = R\left(\frac{1}{4}-\frac{1}{9}\right)$

$\frac{1}{\lambda} = R\times \frac{5}{36}$

$\lambda = \frac{36}{5R}$

Substitute, $R=1.097\times 10^7$

$\lambda = \frac{36}{5\times 1.097\times 10^7}$

$\lambda \approx 32.82 \times 10^{-7}$

$\lambda \approx 3.28 \times 10^{-6} \, m$

Therefore, The wavelength is  $\lambda \approx 3.28 \times 10^{-6} \, m$