Question

calculate the weight of FEO produced from 2g VO and 5.75g of Fe2O3. Also report the limiting reagent. VO + FeO3 -----> FeO + V2O5​

Answer 1

Answer:

given = weight of FeO from 2g VO and 5.75g of Fe2O3.

to find =  limiting reagent = ?

solution =

        intial  or before mole of reaction =  2VO + 3FeO ------->6FeO+V2O5​

                                                                   2/67 + 5.75 /160

                                                                0.0298+ 0.0359

mole after reaction /final mole = (0.0298 -  (0.359 X 2) /3)  0[ 0.0359 X 2][0.0359X1]

Now we can find the moles in the reaction,

VO : Fe2O3 :  FeO3 :V2O5 :

2    :     3       :     6     :   1

mole of FeO  = 2X 0.0359 =  0.0718

therefor, weight of FeO formed = 0.0359  x2 x 72 = 5.18g

the limiting reagent is Fe2O3 which is totally used.