Question

calculate the weight of KMnO4 Contained in 2 liters of 0.15M Solution

Answer 1

47.4gm

Explanation:

Molecular WT of KMnO4=158g

Molarity of KMnO4= 0.15M

Volume =2lit

Now by molarity formula we have

Molarity=number of moles/volumein litres

Number of moles=given weight/molecular wt

ie wt/158

Now putting these values in molarity formula

0.15=wt/158×2

wt=0.15×158×2

wt=47.4gm

Answer