• calculate the weight of kNO3 formed in grams by decomposition of 15.15g of KNO3
2KNO3---->
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Answered by
2
Answer:
Correct option is
B
101 g
S+O
2
⟶SO
2
Moles of S =
32g/mol
16g
=0.5 mol
0.5 mol of S requires 0.5 mol of oxygen.
So, we know that sulphur burns in 0.5 mol oxygen.
The thermal decomposition of Pottasium nitrate:
2KNO
3
⟶2KNO
2
+O
2
1 mol of O
2
is produced by 2 mol of KNO
3
0.5mol of O
2
will be produced by 1 mol of KNO
3
Thus, 1 mole of KNO
3
is required to produce the given amount of oxygen.
1 mol of KNO
3
= molar mass of KNO
3
=101 g
Hence, option B is correct.
Explanation:
Answered by
0
Answer:
vvjg u e51.7.5
Explanation:
81
30.15mmmuwu
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