Question

Calculate the weight of sodium carbonate present in 100 ml of 0.5 molar solution sodium carbonate

Answer 1

Answer:

Molarity = NO. OF MOLES OF SOLUTE / VOLUME OF SOLUTION IN LITRE

HERE

MOLARITY=0.5M

VOLUME of solution =100ml

Molecular mass of Na2C03=23*2+12+16*3=106

Using formula and substituting value we have

0.5= x*1000 / 106*100

X=0.5*106*100/1000

X=5.3g

Or

if we convert me to Litre then

100ml=0.1litre

Mass = moles * molecular mass

=(0.1litre*0.5moles/litre)* 106grams

Mass=5.3grams.