Question

calculate the weight of urea present in 500 ml of 0.1 M urea solution ​

Answer 1

Answer:

5678

Explanation:

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Answer 2

Explanation:

• Urea= NH2- CO- NH2 And we know that Total mass of urea = 60 Mass of nitrogen = 14 Two molecules of nitrogen= 2*14= 28 Percentage of nitrogen = Mass of Nitrogen/(Urea ) x 100 = 28/60 x 100 = 46.6% Hence Percentage of nitrogen in urea is 46%