Calculate the weight of V2O5 produced from 2g of VO and 5.75g if Fe2O3
VO+Fe2O3 ----------> FeO + V2O5
Answers
Answered by
44
First of all we have to write balance equation like
2VO + 3Fe2o3 ---------------> 6Feo + V2o5
here molecular weight of VO is 65 amu and gram of VO is 2 so mole of VO is o.o3
and now
2mol of vo and 3 mol fe2o3 produce 1 mol v2o5
so 0.046 mol consume of Fe2o3 with o.o3 mol Vo
but here is mass of Fe2o3 is 5.75 g so mol of Fe2o3 is 0.035 so here Fe2o3 is limiting reagent
so 0.035 mol of Fe2o3 produce 0.011 mol of V2o5
and mass of V2o5 is 2.18 g
2VO + 3Fe2o3 ---------------> 6Feo + V2o5
here molecular weight of VO is 65 amu and gram of VO is 2 so mole of VO is o.o3
and now
2mol of vo and 3 mol fe2o3 produce 1 mol v2o5
so 0.046 mol consume of Fe2o3 with o.o3 mol Vo
but here is mass of Fe2o3 is 5.75 g so mol of Fe2o3 is 0.035 so here Fe2o3 is limiting reagent
so 0.035 mol of Fe2o3 produce 0.011 mol of V2o5
and mass of V2o5 is 2.18 g
Answered by
5
Answer:
2.18 g
Explanation:
here is mass of Fe2o3 is 5.75 g so mol of Fe2o3 is 0.035 so here Fe2o3 is limiting reagent
so 0.035 mol of Fe2o3 produce 0.011 mol of V2o5
and mass of V2o5 is 2.18 g
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