Calculate the work done by a person in lifting a load of 20kg from the ground and replacing it in 1 m in a table
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Answered by
3
work W=F*S
F=20kgf,S=1m
W=20kgf*1m
W=20kgfm;lets take value of g=10N
W=200Nm
F=20kgf,S=1m
W=20kgf*1m
W=20kgfm;lets take value of g=10N
W=200Nm
Answered by
3
Work done = Change in potential energy
= mg (h₂ - h₁)
= 20 kg × 9.8 m/s² × (1 m - 0 m)
= 196 Joule
Work done to lift the load is 196 Joule
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