Question

calculate the work done for the reversible isothermal expansion of 1 mole of an ideal gas at 27°c ,from a volume of 10dm3 to a volume of 20dm3​

Answer 1

Answer:

Explanation:

Given :

initial volume = 10 dm3 = 10 litre.

final volume = 20 dm3 = 20 litre .

n = 1

R = 25/3

T = 273 + 270 = 543 K

as we know that for reversible isothermal process, work done,W = -2.303 nRT log10 V2 / V1

so substituting the given values :

W = -2.303 * 25/3 * 543 log 2

W = -3126.32 J