Calculate the work done in increasing the velocity of car of mass 1500kg from 30km/h to60km/h
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Answered by
0
Heya!
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Work done = ?
Mass of the car = 1500 kg
Initial velocity = 30 km/h = 25/3 m/s
Final velocity = 60 km/h = 50/3 m/s
Work done = Increase in kinetic energy
Work done = Final kinetic energy - Initial k.e
W.D = 1/2 × 1500 [ (50/3)^2 - (25/3)^2]
USING IDENTITY [ a^2 - b^2 = (a+b) (a-b) ]
W.D = 1/2 × 1500 (50/3 + 25/3) (50/3 - 25/3)
W.D = 1500/2 × 75/3 × 25/3
W.D = 156250 J
W.D = 155.25 kJ
____________________
Hope it helps...!!!
____________________
Work done = ?
Mass of the car = 1500 kg
Initial velocity = 30 km/h = 25/3 m/s
Final velocity = 60 km/h = 50/3 m/s
Work done = Increase in kinetic energy
Work done = Final kinetic energy - Initial k.e
W.D = 1/2 × 1500 [ (50/3)^2 - (25/3)^2]
USING IDENTITY [ a^2 - b^2 = (a+b) (a-b) ]
W.D = 1/2 × 1500 (50/3 + 25/3) (50/3 - 25/3)
W.D = 1500/2 × 75/3 × 25/3
W.D = 156250 J
W.D = 155.25 kJ
____________________
Hope it helps...!!!
Answered by
0
☆☆your answer is here☆
solution:--
w= 1/2×m×(v^2-u^2)
= 1/2×1500×[(60×5/18m/s)^2-(30×5/18m/s)^2]
= 750×[(16.67m/s)^2-(8.33m/s)^2]
= 750×208.5
= 156,375 j
= 156.375 k.j
solution:--
w= 1/2×m×(v^2-u^2)
= 1/2×1500×[(60×5/18m/s)^2-(30×5/18m/s)^2]
= 750×[(16.67m/s)^2-(8.33m/s)^2]
= 750×208.5
= 156,375 j
= 156.375 k.j
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