calculate the work done in kilo joules in lifting a mass of 10kg (at a steady velocity) through a vertical height of 10m?
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Answered by
7
W=F*S
since,F=m*a
here, a=(-g) since, the body is moving away from the centre.
so, W=m*(-g)*S
W=10*(-9.81)*10
W=-981 j
W=-981/1000 kj
W=-0.981 kj
negative (-) sign represents the opposite direction.
since,F=m*a
here, a=(-g) since, the body is moving away from the centre.
so, W=m*(-g)*S
W=10*(-9.81)*10
W=-981 j
W=-981/1000 kj
W=-0.981 kj
negative (-) sign represents the opposite direction.
Answered by
2
Concept:
Work done by any object can be defined as
w = mgh
Where m = mass of the object, g = acceleration due to gravity, and h = height from the ground.
Given:
Mass, m = 10 kg
Vertical height, h = 10 m
Find:
Work done in kilojoules.
Solution:
Work done,
w = mgh
Taking g = 10 m/s²,
w = mgh
w = (10)(10)(10)
w = 1000J
Dividing the work done in joules by 1000 to convert it in kilojoules,
w = 1 kJ
Hence, the work done in lifting a mass of 10kg through a vertical height of 10m is 1 kJ.
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