Question

a body moves with an initial velocity of 5 m/s and uniform acceleration of 0.4 m /s . calculate the velocity after 12 s and distance traveeles in this time

Answer 1

hey u here yrs answer
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given,
initial velocity (u)=5m/s
final velocity (v) we have to find
time (t) =12s
acceleration=0.4m/s^2
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using 1st equation of motion
v=u+at
v=5+0.4*12
v=9.8m/s

Now,
Using 2nd equation of motion
s=ut +1/2at^2
s=5*12+1/2*0.4*(12)^2
s=74.8
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