Find the H. C. F of the following sets of the numbers by any method. numbers are 148,245. answer me fast
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Answered by
3
your answer of this question will be 1 .....if u do according to Euclid division leema
SwarajKarmakar:
if u do prime factorize......then...........148 = 2*2*37*1...........and 245=5*7*7*1...........thus the common factor of the both comes 1
did u got it????
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Answered by
9
Hey!!!
________________
By prime factorization method
2_|148
2 | 74
| 37
5 | 245
7 | 49
| 7
48 = 2 × 2 × 37
245 = 5 × 7 × 7
(There is no common factor)
Hence HCF [ 148 and 245] = 1.
Hope it will helps you:-)
________________
By prime factorization method
2_|148
2 | 74
| 37
5 | 245
7 | 49
| 7
48 = 2 × 2 × 37
245 = 5 × 7 × 7
(There is no common factor)
Hence HCF [ 148 and 245] = 1.
Hope it will helps you:-)
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