Question

Calculate the work done in lifting 200 kg of water through a vertical height of 6 metres
(Assume g = 10 m/s)
A) 5000 J
B) 12000 J
C) 25000 J
D) 15000 J


Answer fast pls

Answer 1

Answer:-

Option (B) 12000 J is correct.

• Work done = 12000 Joules, against the gravity

Explanation:-

Given

• mass of water to be lifted, m = 200 kg
• height for lifting water, h = 6 m
• the magnitude of g to be taken 10 m/s²; so, g = -10 m/s²  (negative because the body needs to be raised against the gravity)

To find

• The work done in lifting the water to an offered height, W =?

Knowledge required

• When work is done against the resistive force like gravity then Work done is equivalent to the potential energy gained by the body while raising.

        W = F · s = (mg) · h = mgh

[ Where symbols W, F, s, m, g and h represent work done, force, displacement, mass, acceleration due to gravity and height respectively ]

Solution

Using the formula

→ W = mgh

(putting values)

→ W = 200 × -10 × 6

→ W = -12000 J

Therefore,

• A work of magnitude 12000 Joules is done against the gravity

Hence, OPTION (B) 12000 J is correct.

Answer 2

Answer:

✠ Given :-

↪ A 200 kg of water through a vertical height of 6 metres.

✠ Find Out :-

↪ Work Done.

✠ Formula Required :-

↪ Work Done = Mass × Gravity × Height

✠ Solution :-

Given in the question :-

◈ Mass = 200 kg

◈ Gravity = 10 m/s

◈ Height = 6 m

ATQ :-

↦ Work Done = 200 × 10 × 6

↦ Work Done = 2000 × 6

➠ Work Done = 12000 J

Therefore, the work done is 12000 J.

Hence, correct options is B) 12000 J