Question

Calculate the work done in lifting a 200kg of water through a vertical distance of 6 m.
Assume g = 10 m/s^2

Answer 1

Hi friend,

Work done= potential energy

Work done = mgh

Work done= 200×6×10

Work done= 1200J (or) 12kj.

Hope this helped you a little!!!!

Answer 2

F=mg

F= 200×10=2000N

Work Done=f×s

=2000×6

=12000J

Hope it helps

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