Question

Find the probability that in a family of 3 children there will be at least one boy​

Answer 1

sample space = {BBB, GGG,BBG, BGB,GBB,GGB, GBG,BGG}. n(s)=8.

Event A={BBB,BBG,BGB,GBB,GGB,GBG,BGG}.

n(A)=7.

P(A)= n(A)/n(s)=7/8
Therefore the probability is 7/8.
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