Find the probability that in a family of 3 children there will be at least one boy
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sample space = {BBB, GGG,BBG, BGB,GBB,GGB, GBG,BGG}. n(s)=8.
Event A={BBB,BBG,BGB,GBB,GGB,GBG,BGG}.
n(A)=7.
P(A)= n(A)/n(s)=7/8
Therefore the probability is 7/8.
MARK ME AS THE BRAINLIEST.
Event A={BBB,BBG,BGB,GBB,GGB,GBG,BGG}.
n(A)=7.
P(A)= n(A)/n(s)=7/8
Therefore the probability is 7/8.
MARK ME AS THE BRAINLIEST.
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